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In the figure below, we must apply a force of magnitude 76 N to hold the block stationary at x = -2.0 cm. From that position we then slowly move the block so thatour force does +3.0 J of work on the spring-block system; the block is then again stationary. What is the block's position (x)? (There are two answers.)__________ cm__________ cm
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kx is F. k*2 = 76 k=38 N/m Now is the right time to do it. 3 + 0. 5k(x1^2-x2^2) = 76(x2-x1) 3+0.5*76(0.02^2 - x2^2) = 76(x2+0.02) 3+0.0152 - 38x2^2 = 76x2 + 1.52 38x^2 + 76x - 1.48=0 figuring it out x= 0. 0193 m = 1.93cm
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