Please answer all the questions Here is evenodd function: function [xe, xo, m] = evenodd(x,n) % Real signal decomposition into even and odd parts % ------------------------------------------------- % [xe, xo, m] = evenodd(x,n) % if any(imag(x) ~= 0) error('x is not a real sequence') end m = -fliplr(n); m1 = min([m,n]); m2 = max([m,n]); m = m1:m2; nm = n(1)-m(1); n1 = 1:length(n); x1 = zeros(1,length(m)); x1(n1+nm) = x; x = x1; xe = 0.5*(x + fliplr(x)); xo = 0.5*(x - fliplr(x)); Problem 2: a. Show that any signal can be decomposed into it an even and an odd component. Is the decomposition unique? b. Using the evenodd function, decompose the following sequences into their even and odd components Plot the original sequence and its components on one figure using subplot commands. ·n(n)-cos(0.2πn + π/4), -20 n-20 · T2(n) = e-0.05n sin(0.1πn + π/3), 0 n-100 Problem 2: a. Show that any signal can be decomposed into it an even and an odd component. Is the decomposition unique? b. Using the evenodd function, decompose the following sequences into their even and odd components Plot the original sequence and its components on one figure using subplot commands. ·n(n)-cos(0.2πn + π/4), -20 n-20 · T2(n) = e-0.05n sin(0.1πn + π/3), 0 n-100


Are there any questions left?
New questions in the section Engineering
Sign up for the IQClass
Answers from experts with no ads!
Sign up
Develop soft skills on BrainApps
Complete the IQ Test
Made with love
This website uses cookies to make IQClass work for you. By using this site, you agree to our cookie policy

Pleased to see you again

IQClass unlocks the learning potential of every child
  • Master useful skills
  • Improve learning outcomes
  • Share your knowledge
Create an account
Sign in
Recover lost password
Or log in with

Create an account

IQClass unlocks the learning potential of every child
  • Master useful skills
  • Improve learning outcomes
  • Share your knowledge
Create an account
Sign Up
Or sign up with
By signing up, you agree to the Terms of use and Privacy policy.
Looking for an answer to a question you need help with?
you have баллов