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An explorer is caught in a whiteout (in which the snowfall is so thick that the ground cannot be distinguished from the sky) while returning to base camp. He wassupposed to travel due north for 4.9 km, but when the snow clears, he discovers that he actually traveled 7.8 km at 53° north of due east.(a) How far must he now travel to reach base camp?km(b) In what direction must he travel?° (counterclockwise from due east)
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Let the north and the east be y and x directions. There is an actual displacement. y=7.8*sin49. x=7.8*cos49. So far away to the base came. (y-4.4)^2+x^2=r^2 so r=5.3(km) The direction is shown in the vector of direction. (0,4.4)-(7.8*cos49,7.8*sin49)=(-5.1,-1.5). so the angle 0 tan0 = 1.5/5.1 so 0 = 196(deg) (from east)
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