An insurance sales representative selects 3 policies to review. The group of policies she can select from contains 8 life policies, 5 automobile policies, and 2 homeowner policies. Find the probability of selecting”(a) All life policies (b) Both homeowner policies (c) All automobile policies (d) 1of each policy (e) 2 life policies and 1 automobile policy
I will come up with a problem to indicate the process and leave the rest to you. (a) 3 life policies. First 8/15, second (no replacement) 7/14, third 6/13. The final probability is calculated by taking the individual probabilities and dividing them by the 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 888-666-1846 The start should be given by this.
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