ë for one line of the hydrogen spectrum is .4118 x 10-4 cm. Use this value in the Rydberg equation to calculate the RH value using n1 = 2, and n2 = 5 I have tried to figure this out so many times, found the same answer, and it's always wrong. please help
I thought I showed you how to do this, but as I remember, I used 6 for n2. I am pretty sure I know what the problem is. If we use the known R value of 1. 097 x 10^7 and substitute n1 = 1 and n2 = 5, we get 1/wavelength = 1.097E7(1/4-1/25) 1/wavelength = 1.097E7(0.21) wavelength = 4. 34 x 10^-7 meters which is NOT 0. 4118 cm (4. 118 x 10^-7 m) In fact, if we substitute 4 for n2 we get 4861 A, n2 = 5 we get 4341 A, n2 = 6, we get 4102 A and n2 = 7 we get 3970 A. None of those are 4118 A (I switched to Angstroms = A and 1 A = 10^-8 cm). I think you can do this calculation if the cows come home and you don't get the accepted value of R. Take a look at your problem. You have to be sure you are using 888-739-5110 888-739-5110 888-739-5110 888-739-5110 888-739-5110 888-739-5110 888-739-5110 888-739-5110 888-739-5110 is 888-739-5110 888-739-5110 888-739-5110 888-739-5110 is 888-739-5110 888-739-5110 888-739-5110 888-739-5110 is 888-739-5110 888-739-5110 888-739-5110 888-739-5110 888-739-5110 888-739-5110 is 888-739-5110 888-739-5110 888-739-5110 888-739-5110 888-739-5110 888-739-5110 888-739-5110 888-739-5110 888-739-5110 888-739-5110 888-739-5110 888-739-5110 888-739-5110 888-739-5110 888-739-5110 888-739-5110 888-739-5110 888-739-5110 888-739-5110 888-739-5110 888-739-5110 888-739-5110 888-739-5110 But I can tell you that 4118 A is not a line of the Balmer Series.
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