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A person of mass 75 kg stands at the center of a rotating merry-go-round platform of radius 3.0 m and moment of inertia 1200 kg·m2. The platform rotates withoutfriction with angular velocity 1.0 rad/s. The person walks radially to the edge of the platform.Calculate the angular velocity when the person reaches the edge.


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PPJack 1 answer

According to the law of the law of the law of the law of the law of the law. I1w1 = I2w2 1200 * 1 = (1200 + 75 * 3 ^ 2) * w2 Hence, therefore. w2 = 0. 64 radians/sec

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