Suppose 80% of the incoming email messages for a college’s computer system are spam.1. Use the CLT to approximate the probability that in a random sample of 200 incoming email messages at this college, the sample proportion of these messages that arespam would exceed .75.answer: P(X >0.75) = P{ z > (0.75 - 0.80) / square root[0.80(1-0.80) / 200] } = P( z > -1.768 )Using the standard normal tables P( z > -1.768 ) = 0.96152. Would your answer to question 1 be larger, smaller, or the same if the (population) proportion of spam messages were .77 rather than .80? Explain briefly.
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