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Calculate the heat of decomposition for this process at constant pressure and 25°C. (Look up the standard enthalpy of formation of the reactant and products in thetable; ?H°f(BaCO3(s)) = -1218.8 kJ/mol, ?H°f (BaO(s)) = -558.2 kJ/mol and ?H°f (Na2CO3(s)) = -1130.9 kJ/mol, ?H°f (Na2O(s)) = -415.89 kJ/mol.)MgCO3(s) ? MgO(s) + CO2(g)
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MgCO3(s) --> MgO(s) + CO2(g) ? H0rxn= ? What is the formula? H0rxn=Snp? H0f (products) - Snr? H0f(reactants) =[1mol*? H0f(CO2(g))+1mol*? H0f(MgO(s))]-[1mol*? H0f(MgCO3(s))] =[1mol*-393.1kJ/mol+1mol*-415.89kJ/mol]-[1mol*-1130.9kJ/mol] =+321.91kJ thereofore, heat of decopmposition of this process= +321.91kJ
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