A 600 N uniform rectangular sign 4.00 m wide and 3.00 m high is suspended from a horizontal, 6.00-m-long, uniform, 90-N rod. The left end the rod is supported by a hinge and the right end is supported by a thin cable making a 30.0° angle with the vertical. (a) Find the tension, T, in the cable. ____N (b) Find the horizontal and vertical components of force exerted on the left end of the rod by the hinge. (Take up and to the right to be the positive directions.) horizontal component_____ N vertical component________N
forces right on rod = 0 = Fwallhorizontal - Tsin 30 So Fwall horizontal = 513/2 = 257 N forces up on rod = Fupwall +513 cos 30 forces down on on rod = 690 So, that's right. Fupwall = 690 - 444 = 246 N
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Will assume that it goes out to the end. Take a moment to think about the hinge. T * 6 * cos 30 = 5. 2 T counterclockwise 600*4 + 90*3 = 2670 clockwise so T = 2670/5. 2 = 513 Newtons tension
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Tell me how far the middle of the sign is from the wall, from the picture. Is the middle of the sign in the middle of the rod (3 meters from wall) or is it all the way out (4 meters out)
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